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Prove that √3 is irrational noAnswer: Let √3 be rational no.√3 = a/b, b is not equal to 0a and b are co prime a= √3b a^2 =3b^2 (sq. on both sides). ----------(1)if a^2 is divisible by 3 and so a is also divisible by 3Using another integer c, such thata = 3c(a)^2 = (3c)^2. (sq. on both sides) a^2=9c^2 ---------(2)3b^2 = 9c^2 (from 1) b^2=3c^2 If b^2 is divisible by 3 and so b is divisible by 3This implies that a and b have 3 in common & this is a contradiction to the fact that a and b are co-prime.Hence, √3 cannot be expressed as p/q OR it can be said that √3 is an irrational no. |
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Answer» It is RIGHT!!!!!!!!!!! |
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