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Prove that 2root5is irrational |
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Answer» Step-by-step explanation: Suppose, it can be written in firm of p/q,and q is not equal to zero. When p and q are relative PRIME numbers √5 = p/q, q is not equal to 0~~eq (1) Where p and q are relative prime numbers Taking square 5=p2/q2 5=p2/q.q Taking ONE q on opposite side 5q=p2/q~~(2) Since p and q being relative prime No's , q cannot divide p and p2 As l.h.s of eq(2) is an integer i.e; nq Hence l.h.s of eq(2) is not equal to R.H.s So our assumption is wrong So √5 is an irrational number. |
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