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Prove that 2√3 is an irrational -------- 5​

Answer»

We can prove it by contradictory method..

We assume that 2 + √3 is a rational number.

=> 2 + √3 = p/Q , where p & q are integers, ‘q’ not = 0.

=> √3 = (p/q) - 2

=> √3 = (p - 2q)/ q ………… (1)

=> here, LHS √3 is an irrational number.

But RHS is a rational number.. Reason- the difference of 2 integers is always an integer. So the numerator (p- 2q) is an integer.

& the denominator ‘q’ is an integer.&‘q’ not = 0

This WAY, all conditions of a rational number are SATISFIED.

=> RHS (p- 2q)/q is a rational number.

But , LHS is an irrational.

=> LHS of….. (1) is not = RHS.

=> Our assumption, that 2 + √3 is a rational number, is incorrect..

=> 2 + √3 is an irrational number

ItzDopeGirl❣


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