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Prove that- √2+√2+√2+2cos8theta=2cos theta |
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Answer» Listen i will represent theta by ¢and...... you must know that (cos2¢=2cos^2¢-1),,,,,Solving LHS...,√2+√2+√2+2cos8¢......,√2+√2+√2(1+cos8¢).....,√2+√2+√2(2cos^2 4¢).....by applying identity....,√2+√2+2cos4¢.......,√2+√2(1+cos4¢)......,√2+√2(2cos^2 2¢).....,√2+2cos 2¢.......,√2(1+cos 2¢)......,√2(2cos^2 ¢).....,2cos¢......=RHS...,,,,,,,HENCE PROVED.. Could u send ans of ths que |
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