Prove that (1+tanA - secA) × (1+tanA+ secA) = 2tanA

1.	Prove that (1+tanA - secA) × (1+tanA+ secA) = 2tanA
Answer» ong>Step-by-step explanation: => let multiply 1 + tanA + SECA + tanA + tan² + tanAsecA - secA - secAtanA - secA² => let CANCEL same terms 1 + 2tanA + tan²A - sec²A ( :- we know that sec²A - tan²A = 1 then multiply with -1 => tan²A - sec²A = -1 ) 1 + 2tanA - 1 = 2tanA ( :- HENCE proved) I HOPE this will help you dear.. Always stay safe and stay healthy..

Answer»

ong>Step-by-step explanation:

=> let multiply

1 + tanA + SECA + tanA + tan² + tanAsecA - secA - secAtanA - secA²

=> let CANCEL same terms

1 + 2tanA + tan²A - sec²A

( :- we know that sec²A - tan²A = 1 then

multiply with -1 => tan²A - sec²A = -1 )

1 + 2tanA - 1 = 2tanA

( :- HENCE proved)

I HOPE this will help you dear..

Always stay safe and stay healthy..

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Prove that (1+tanA - secA) × (1+tanA+ secA) = 2tanA​

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Prove that (1+tanA - secA) × (1+tanA+ secA) = 2tanA