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Prove that (1+tanA-secA)×(1+tanA+secA) |
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Answer» ong>ANSWER: Answer Open in ANSWR app tanA−secA+1 tanA+secA−1
= cosA 1+sinA
Taking L.H.S.- tanA−secA+1 tanA+secA−1
= tanA−secA+1 (tanA+secA)−(SEC 2 A−tan 2 A)
[∵1+tan 2 A=sec 2 A] = tanA−secA+1 (tanA+secA)−(secA+tanA)(secA−tanA)
= tanA−secA+1 (tanA+secA)(1−(secA−tanA))
= tanA−secA+1 (tanA+secA)(1−secA+tanA)
=tanA+secA = cosA sinA
+ cosA 1
= cosA 1+sinA
= R.H.S. Hence proved. |
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