1.

Prove that √1-sinA/1+sinA=secA-tanA​

Answer»

LHS

=√(1 + sin∅)/√(1 - sin∅)

=√(1 + sin∅) × √(1 + sin∅)/√(1 -sin∅)×√(1 +sin∅)

=√(1 + sin∅)²/√(1 -sin²∅)

=(1 + sin∅)/√cos²∅

=(1 + sin∅)/cos∅

=1/cos∅ + sin∅/cos∅

=sec∅ + tan∅

=RHS


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