1.

Prove that [1/(sec²x-cos²x) + 1/(cosec²x-sin²x)] sin²x cos²x = (1-sin²x cos²x)/(2+sin²x cos²x)

Answer»

Prove that

[1/(sec²x-cos²x) + 1/(cosec²x-sin²x)] sin²x cos²x =

(1-sin²x cos²x)/(2+sin²x cos²x)



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