Prove that 1/(k+1)(k+2)[k³+9k+6k²+4/4(k+3)]=(k+1)(k+4)/4(k+2)(k+3)

1.	Prove that 1/(k+1)(k+2)[k³+9k+6k²+4/4(k+3)]=(k+1)(k+4)/4(k+2)(k+3)
Answer» k³ + 9k + 6k² + 4 ko k + 3 se divide kar do solve ho jayega.... This?

Discussion