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Prove that:-√1+cosA÷ 1+cosA + √1- cosA÷ 1+cosA= 2 cosecA ( it is whole root over in LHS but separately). |
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Answer» Answer : LHS=RHS 1-cosA=2sin²(½A) 1+cosA≈2cos²(½A) Hence, LHS=√{sin²(½A)/cos²(½A)}=TAN(½A) RHS=(1/s)-(c/s)≈(1-c)/s=2sin²(½A)/2sin(½A)cos(½A)=SIN(½A)cos(½A) =tan(½A) ∴LHS=RHS Step-by-step EXPLANATION: |
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