1.

Prove that:-√1+cosA÷ 1+cosA + √1- cosA÷ 1+cosA= 2 cosecA ( it is whole root over in LHS but separately).​

Answer»

Answer :  LHS=RHS

1-cosA=2sin²(½A)

1+cosA≈2cos²(½A)

Hence,

LHS=√{sin²(½A)/cos²(½A)}=TAN(½A)

RHS=(1/s)-(c/s)≈(1-c)/s=2sin²(½A)/2sin(½A)cos(½A)=SIN(½A)cos(½A)

=tan(½A)

∴LHS=RHS

Step-by-step EXPLANATION:



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