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Prove that (1) (AUB)xC=(AxC)U(BxC) |
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Answer» So (AUB)×C=(A×C)U(B×C) LetA={1,2} and B={3,4} and C={5,6}So (AUB)={1,2,3,4} so (AUB)×C={(1,5),(1,6),(2,5),(2,6),(3,5),(3,6)}(A×C)={(1,5),(1,6),(2,5),(2,6)}And(B×C)={(3,5),(3,6),(4,5),(4,6)}So (A×C)U(B×C)={(1,5),(1,6),(2,5),(2,6),(3,5),(3,6)} |
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