Prove thae following as irrational number √3+√7

1.	Prove thae following as irrational number √3+√7
Answer» Step-by-step EXPLANATION: √3+√7 Let a rational no. equal to p/Q where q =0 √3+√7=p/q √3=p/q-√7 squaring both sides p^2/q^2+7-2p/q√7=3 p^2/q^2+4=2p/q√7 p/q+4=2√7 p/q+2=√7 p/q +2 is a rational number √7 is a irrational number a rational number and a irrational number can NEVER be equal so our supposition is wrong Hence proved that √3+√7 is a irrational number

Answer»

Step-by-step EXPLANATION:

√3+√7 Let a rational no.

equal to p/Q where q =0

√3+√7=p/q

√3=p/q-√7

squaring both sides

p^2/q^2+7-2p/q√7=3

p^2/q^2+4=2p/q√7

p/q+4=2√7

p/q+2=√7

p/q +2 is a rational number

√7 is a irrational number

a rational number and a irrational number can NEVER be equal so our supposition is wrong

Hence proved that √3+√7 is a irrational number

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Prove thae following as irrational number √3+√7​

√3+√7 Let a rational no.

equal to p/Q where q =0

√3+√7=p/q

√3=p/q-√7

squaring both sides

p^2/q^2+7-2p/q√7=3

p^2/q^2+4=2p/q√7

p/q+4=2√7

p/q+2=√7

p/q +2 is a rational number

√7 is a irrational number

a rational number and a irrational number can NEVER be equal so our supposition is wrong

Hence proved that √3+√7 is a irrational number

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Prove thae following as irrational number √3+√7