Prove itCos(π/2-x)cos(π/2-y)-sin(π/2-x)sin(π/2-y)=-cos(x+y)

1.	Prove itCos(π/2-x)cos(π/2-y)-sin(π/2-x)sin(π/2-y)=-cos(x+y)
Answer» Answer: LHS=RHS Step-by-step explanation: COS(π/2 - x) cos(π/2 - y) - SIN(π/2 - x) sin(π/2 - y) = -cos(x+y) sinx siny - COSX cosy = -(cosx cosy - sinx siny) sinx siny - cosx cosy = sinx siny - cosx cosy LHS = RHS Hence Proved

Answer»

Answer:

LHS=RHS

Step-by-step explanation:

COS(π/2 - x) cos(π/2 - y) - SIN(π/2 - x) sin(π/2 - y) = -cos(x+y)

sinx siny - COSX cosy = -(cosx cosy - sinx siny)

sinx siny - cosx cosy = sinx siny - cosx cosy

LHS = RHS

Hence Proved

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Prove itCos(π/2-x)cos(π/2-y)-sin(π/2-x)sin(π/2-y)=-cos(x+y)​

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Prove itCos(π/2-x)cos(π/2-y)-sin(π/2-x)sin(π/2-y)=-cos(x+y)