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prove irrational( 3+root 2) |
| Answer» Let 3+√2 is an rational number.. such that3+√2 = a/b ,where a and b are integers and b is not equal to zero ..therefore,3 + √2 = a/b√2 = a/b -3√2 = (3b-a) /btherefore, √2 = (3b - a)/b is rational as a, b and 3 are integers..It means that √2 is rational....But this contradicts the fact that √2 is irrational..So, it concludes that 3+√2 is irrational..hence proved. | |