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Prove : (1-sinA) /(1+sinA) = 1+tanA^2 - 2tanAsecA |
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Answer» Step-by-step explanation: 1-sinA/1+sinA =(1-sinA)²/1-sin²A =(1+sin²A-2sinA)/cos²A =sec²A+tan²A-2tanAsecA =1+tan²A+tan²A-2tanAsecA =1+2tan²A-2tanAsecA |
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