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Proton of mass m collides elastically with a particle of unknown mass at rest. After the collision, the proton and the unknown particle are seen moving at an angle of 90 with respect to each other. The mass of unknown particle is |
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Answer» # Answer- m # Explaination- Applying law of conservation of momentum ALONG x-axis m1u = m1v1.co45 + m2v2.cos45 m1u = 1/√2 (m1v1+m2v2) ...(1) Applying law of conservation of momentum along y-axis 0 = m1v1.sin45 - m2v2.sin45 0 = 1/√2 (m1v1-m2v2) ...(2) COEFFICIENT of restitution e=(v2-v1.cos90)/ucos45 1 = √2.v2/u u = √2v2 ...(3) Solving (1)(2)&(3) we get m1=m2=m Hence MASS of unknown particle will be m. |
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