Proportional of a and cis b then prove that a, C,(b) If b is the mean

1.	Proportional of a and cis b then prove that a, C,(b) If b is the mean proportional of a and c, prove that the mean proportional of a? +62 and b? + c?is ab + bc.(c) If b is the mean proportional of a and c, prove thatab + bc + ca= abc.a+b+c3
Answer» Answer: please reply if you had understood . Step-by-step explanation: Since, B is the mean PROPORTIONAL between a and C. So B2 = ac. L.H.S. = a2 – b2 + c2/a-2 – b-2 + c-2 = a2 – b2 + c2/1/a2 – 1/b2 + 1/c2 = (a2 – b2 + c2)/b2c2 – a2c2 + a2b2/a2b2c2 = a2b2c2 (a2 – b2 + c2)/b2c2 – b4 + a2b2 = b4 × b2(a2 – b2 + c2)/b2(c2 – b2 + a2) b4 = R.H.S. Hence proved.

Proportional of a and cis b then prove that a, C,(b) If b is the mean proportional of a and c, prove that the mean proportional of a? +62 and b? + c?is ab + bc.(c) If b is the mean proportional of a and c, prove thatab + bc + ca= abc.a+b+c3

Answer»

Answer:

please reply if you had understood .

Step-by-step explanation:

Since, B is the mean PROPORTIONAL between a and C. So B2 = ac.

L.H.S. = a2 – b2 + c2/a-2 – b-2 + c-2

= a2 – b2 + c2/1/a2 – 1/b2 + 1/c2

= (a2 – b2 + c2)/b2c2 – a2c2 + a2b2/a2b2c2

= a2b2c2 (a2 – b2 + c2)/b2c2 – b4 + a2b2

= b4 × b2(a2 – b2 + c2)/b2(c2 – b2 + a2)

b4 = R.H.S.

Hence proved.

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Proportional of a and cis b then prove that a, C,(b) If b is the mean proportional of a and c, prove that the mean proportional of a? +62 and b? + c?is ab + bc.(c) If b is the mean proportional of a and c, prove thatab + bc + ca= abc.a+b+c3​

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Proportional of a and cis b then prove that a, C,(b) If b is the mean proportional of a and c, prove that the mean proportional of a? +62 and b? + c?is ab + bc.(c) If b is the mean proportional of a and c, prove thatab + bc + ca= abc.a+b+c3