Propionic acid with `Br_(2)`/`P` yields a dibromo product. Its structure would beA. `CH_(2)Br-CHBr-COOH`B. `H-underset(Br)underset(|)overset(Br)overset(|)(C)-CH_(2)COOH`C. `CH_(2)Br-CH_(2)-COBr`D. `CH_(3)-underset(Br)underset(|)overset(Br)overset(|)(C)-COOH`

Propionic acid with `Br_(2)`/`P` yields a dibromo product. Its structu

1.	Propionic acid with `Br_(2)`/`P` yields a dibromo product. Its structure would beA. `CH_(2)Br-CHBr-COOH`B. `H-underset(Br)underset(\|)overset(Br)overset(\|)(C)-CH_(2)COOH`C. `CH_(2)Br-CH_(2)-COBr`D. `CH_(3)-underset(Br)underset(\|)overset(Br)overset(\|)(C)-COOH`
Answer» Correct Answer - D `alpha`-hydrogen is substituted by bromine.

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Propionic acid with `Br_(2)`/`P` yields a dibromo product. Its structure would beA. `CH_(2)Br-CHBr-COOH`B. `H-underset(Br)underset(|)overset(Br)overset(|)(C)-CH_(2)COOH`C. `CH_(2)Br-CH_(2)-COBr`D. `CH_(3)-underset(Br)underset(|)overset(Br)overset(|)(C)-COOH`

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