1.

Propionic acid with Br_(2)//P yields a dibromo product. Its structure would be

Answer»

`CHBr_(2)-CH_(2)COOH`
`CH_(2)Br-CH_(2)-COBr`
`CH_(3)-CBr_(2)-COOH`
`CH_(2)Br-CHBR-COOH`

Solution :Bromination occurs at `alpha`-position.
`CH_(3)-overset(alpha)(C)H_(2)-COOH underset(-HBr)overset(Br_(2)//P)CH_(3)-CHBr-COOH underset(-HBr)overset(Br_(2)//P)toCH_(3)-CBr_(2)-COOH`


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