1.

Professor needs a lens of power -5.5 D for correcting a distant vision. What is the focal length of the lens required for correcting the distant vision?

Answer»

0.18 metres Explanation:since the formula for refractive power of lens is given by,, D=1÷f that is f=1÷D , SUBSTITUTE the VALUE of d in the equation, we GET f=1÷-5.5=-0.18181=-0.18metrs since distance can't be in negative so by neglecting negative SIGN, we have the answer as 0.18 metres.



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