1.

Problem seto1. Select the appropriate alternative.(1) In A ABC and A PQR, in a oneto one correspondenceABBC CAQR PR PO- then(A) A POR ~ A ABC(B) A PQR ~ A CAB(C) A CBA ~ A POR(D) A BCA - A PORRLFig. 1.67

Answer»

triangle PQR ~ triangle CAB



Discussion

No Comment Found