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Problem seto1. Select the appropriate alternative.(1) In A ABC and A PQR, in a oneto one correspondenceABBC CAQR PR PO- then(A) A POR ~ A ABC(B) A PQR ~ A CAB(C) A CBA ~ A POR(D) A BCA - A PORRLFig. 1.67 |
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Answer» triangle PQR ~ triangle CAB |
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