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Problem 7.1sin x-sin xlff(x) =14-x2 +, then the domain of f(x) isT.

Answer»

For , domain of √4-x²

Its should be ≥ 0=> 4-x² ≥ 0=> x²≤4 ... so x is [-2,2]

now for domain of √|sinx|-sinx , it should be > 0

=> |sinx|> sinx so, sinx must be negetive because |sinx| will always be positive., so x <0

so, net domain is [-2,0)

option D


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