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Probabilities that a husband and wife be alive 20 years from now is given by 0.3 and13)0.9 respectively. Find the probability that in 20 yearsc)neither will alive.a)bothb) at least one and |
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Answer» Let A be the event that a husband will be alive after 20 yrs. Let B be the event that a wife will be alive after 20 yrs. Now, PA = 0.8; PB = 0.9 Now, PA = 1-PA = 1 - 0.8 = 0.2 Now, PB 1 - PB = 1 - 0.9 = 0.1 a.Probability that both of them are alive = PA . PB = 0.8×0.9 = 0.72 b.Probability that none of them is alive = PA . PB = 0.2×0.1 = 0.02 c. Probability that at least one of them is alive = 1 - 0.02 = 0.08 Like my answer if you find it useful! thax for that..!!😍 |
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