1.

Probabilities that a husband and wife be alive 20 years from now is given by 0.3 and13)0.9 respectively. Find the probability that in 20 yearsc)neither will alive.a)bothb) at least one and

Answer»

Let A be the event that a husband will be alive after 20 yrs.

Let B be the event that a wife will be alive after 20 yrs.

Now, PA = 0.8; PB = 0.9

Now, PA = 1-PA = 1 - 0.8 = 0.2

Now, PB 1 - PB = 1 - 0.9 = 0.1

a.Probability that both of them are alive = PA . PB

= 0.8×0.9 = 0.72

b.Probability that none of them is alive = PA . PB

= 0.2×0.1 = 0.02

c. Probability that at least one of them is alive

= 1 - 0.02 = 0.08

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