Pressure of 1 g of an ideal gas A at 27 °C is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressurebecomes 3 bar. Find a relationship between their molecular masses.

Pressure of 1 g of an ideal gas A at 27 °C is found to be 2 bar. When

1.	Pressure of 1 g of an ideal gas A at 27 °C is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressurebecomes 3 bar. Find a relationship between their molecular masses.
Answer» MASS of gas A , WA = 1gMass of gas B, WB = 2gPressure exerted by the gas A = 2 barTotal pressure due to both the gases = 3 barIn this case temperature & volume remain constantNow if MA & MB are MOLAR masses of the gases A & B respectively,thereforepA V= WA RT/MA & Ptotal V = (WA/MA + WB/ MB) RT= 2 X V = 1 X RT/MA & 3 X V = (1/MA + 2/MB)RTFrom these two EQUATIONS, we get3/2 = (1/MA + 2/MB) / (1 /MA) = (MB + 2MA) / MBThis result in 2MA/ MB = (3/2) -1 = ½OR MB = 4MAThus, a relationship between the molecular masses of A and B is given by4MA = MB ......Hope this will HELP u.... Follow me..