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PR, S 8 PR T SN3 यदि A+B+ C =90° a‘ सिद्ध कीजिए-C +tanC tan A =1<3 B s e तकहरणtan A tan B + tan B tan |
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Answer» A + B + C = 90° → B + C = 90°−A and tan (B+C)=tan(90°−A) and (tanB+tanC)/(1−tanBtanC)= cotA=cosA/sinA (tanB+tanC)/(1−tanBtanC)= 1/tanAor (tanB+tanC)tanA= (1−tanBtanC) →tanAtanB+tanAtanC =1−tanBtanC hence tanAtanB+tanAtanC+ tanBtanC=1 or tanAtanB+tanBtanC+ tanCtanA=1 Like my answer if you find it useful! |
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