1.

PR, S 8 PR T SN3 यदि A+B+ C =90° a‘ सिद्ध कीजिए-C +tanC tan A =1<3 B s e तकहरणtan A tan B + tan B tan

Answer»

A + B + C = 90°

→ B + C = 90°−A

and tan (B+C)=tan(90°−A)

and (tanB+tanC)/(1−tanBtanC)= cotA=cosA/sinA

(tanB+tanC)/(1−tanBtanC)= 1/tanAor (tanB+tanC)tanA= (1−tanBtanC)

→tanAtanB+tanAtanC =1−tanBtanC

hence tanAtanB+tanAtanC+ tanBtanC=1

or tanAtanB+tanBtanC+ tanCtanA=1

Like my answer if you find it useful!



Discussion

No Comment Found