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PQRS is a cyclic quadrilateral with PQ = 11 RS = 19. M and N are points on PQ and RS respectively such that PM = 6, SN = 7, and MN = 27. The length of the line segment formed when MN is extended from both side until it reaches the circle is ? |
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Answer» ong>ANSWER: Given PQRS is a cyclic QUADRILATERAL. ::Opposite angles of a cyclic quadrilateral are supplementary → Z PSR + < PQR = 180° Z PQR = 180° - 110° → Z PQR = 70° (2)2 * Z PQR = m(arc PR){The measure of an inscribed angle is half the measure of the arc intercepted by it.} m(arc PR) = 140° m(arc PQR) = 360° -140° = 220° {Using Measure of a major arc = 360°- measure of its corresponding minor arc} (3)side PQ = side RQ ::m(arc PQ) = m(arc RQ){Corresponding arcs of congruent chords of a circle (or congruent circles) are congruent} = m(arc PQR) = m(arc PQ) + m(arc RQ) = m(arc PQR) = 2 x m(arc PQ) = m(arc PQ) = 110° (4)In A POR, PQR + < QRP + Z RPQ = 180°{Angle sum property} → Z PRQ + 2 RPQ = 180° - Z PQR → 22 PRQ = 180° - 70° {::side PQ = side RQ} = Z PRQ = 55° I KNOW IT'S MESSED UP BUT PLZ MANAGE PLZ MARK AS BRAINLEST!! |
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