1.

Pq parellel to oqplz help me i will mark the first answer as brainlist and do it in correct way ​

Answer»

In ΔPOQ, we have

DE∥OQ(Given)

By Basic proportionality THEOREM, we have

EQ

PE

=

DO

PD

…(i)

Similarly,

In ΔPOR, we have

DF∥OR(Given)

DO

PD

=

FR

PF

…(II)

Now, from (i) and (ii), we have

EQ

PE

=

FR

PF

⇒EF∥QR

[APPLYING the CONVERSE of Basic proportionality Theorem in ΔPQR]



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