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Pq parellel to oqplz help me i will mark the first answer as brainlist and do it in correct way |
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Answer» In ΔPOQ, we have DE∥OQ(Given) By Basic proportionality THEOREM, we have EQ PE
= DO PD
…(i) Similarly, In ΔPOR, we have DF∥OR(Given) ∴ DO PD
= FR PF
…(II) Now, from (i) and (ii), we have EQ PE
= FR PF
⇒EF∥QR [APPLYING the CONVERSE of Basic proportionality Theorem in ΔPQR] |
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