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`PQ` is an infinite current carrying conductor. `AB` and `CD` are smooth conducting rods on which a conductor `EF` moves with constant velocity `v` as shown. The force needed to maintain constant speed of `EF` is A. `1/(VR)[(mu_0IV)/(2pi) ln (b)/(a)]^2`B. `v/R[(mu_0IV)/(2pi)ln(a)/(b)]^2`C. `v/R[(mu_0IV)/(2pi)ln(b)/(a)]^2`D. None of these |
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Answer» Correct Answer - A `B_x=mu_0/(2pi)I/x` `de=B_x vdx=mu_0/(2pi) I/x v dx` `e=int_a^bde(mu_0Iv)/(2pi) ln (b/a)` `i=e/R=(mu_0Iv)/(2pir)ln(b/a)=`induced current `dF=(i)(dx)B_x` `[(mu_0Iv)/(2piR)ln(b/a)][mu_0/(2pi)I/x]dx` `F=int_a^bdF` |
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