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PQ and RS are two parallel chords of a circle whose centre is O and radius is 10 cm. If PQ =16cm and RS=12cm, find the distance between PQ and RS, If they lie on the same side of the Centre O. |
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Answer» by the use of pythagoras theorem `OM^2 = OP^2 - PM^2 = (10)^2 - (8)^2 = 100 - 69 = 36` `OM= 6`cm `ON^2 = OR^2 - RN^2 = (10)^2 - (6)^2 = 100-31= 64` `ON= 8`cm `MN=ON-OM= 8-6= 2`cm `MN=2 `cm |
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