1.

Power in a balanced 3-phase system is measured by the two-watt meter method and it is found that the ratio of the two readings is 2 to 1. What is the power factor of the system?

Answer»

We are given that W1 :W2 = 2:1.

Hence, W1/W2 = r = 1/2 = 0.5.

cosφ = (1 + r)/(2√(1 - r + r2)) = (1 + 0.5)/(2√(1 - 0.5 + 0.52)) = 0.866 lag



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