Potential energy of a particle at position x is given by u=x^2-5x which will be equilibrium position of pqrticle

Potential energy of a particle at position x is given by u=x^2-5x whic

1.	Potential energy of a particle at position x is given by u=x^2-5x which will be equilibrium position of pqrticle
Answer» tion:The potential energy function for a system is given by U(x)=−4x3+5x2+7x, where x is in meters and U is in Joules.a) Determine the force Fx on the particle as a function of x.b) For what values of x is the force equal to zero?c) PLOT U(x) versus x and Fx versus x and INDICATE the POINTS of stable and unstable equilibrium.Potential Energy and Force:When an object has potential energy, either gravitational, elastic or some other type, it has a force acting on it. The force on the object is the negative derivative of the potential energy function. The graph of this function SHOWS locations of stable and unstable equilibrium.Answer and Explanation:(a) The force equation is F(x)=12x2−10x−7(b) The force is zero at x = -0.453 m and 1.29 m.(c) There are TWO positions of equilibrium,.

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Potential energy of a particle at position x is given by u=x^2-5x which will be equilibrium position of pqrticle

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