Positions of two particles A and B as a function of time are given by XA=−3t2+8t+c and YB=10−8t3. The velocity of B with respect to A at t=1 is √v. Find v [in m2/s2]

Positions of two particles A and B as a function of time are given by

1.	Positions of two particles A and B as a function of time are given by XA=−3t2+8t+c and YB=10−8t3. The velocity of B with respect to A at t=1 is √v. Find v [in m2/s2]
Answer» Positions of two particles $A$ and $B$ as a function of time are given by $X_{A} = - 3 t^{2} + 8 t + c$ and $Y_{B} = 10 - 8 t^{3}$ . The velocity of $B$ with respect to $A$ at $t = 1$ is $\sqrt{v}$ . Find $v$ [in $m^{2} / s^{2}$ ]

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Positions of two particles A and B as a function of time are given by XA=−3t2+8t+c and YB=10−8t3. The velocity of B with respect to A at t=1 is √v. Find v [in m2/s2]

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