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Answer»

Urn A ---->  6R + 4W = 10 Balls

Urn B ---->  2R + 6W = 8 Balls 

Urn C ---->  1R + 5W = 6 Balls

 

E1 = The ball is selected from urn A

E2 = The ball is selected from urn B

E3 = The ball is selected from urn C

 

Therefore P(E1) = P(E2) = P(E3) = 1/3

Let A = drawing a red ball.

so,  P(A/E1) = 6/10 

   P(A/E2) = 2/8 

    P(A/E3) = 1/6

 

By Baye's Theorem

Required Probability = P(E1/A)

 ----------------------- > = ( 1/3 * 6/10 )  /  (  1/3 * 6/10 +  1/3 * 2/8  +  1/3  * 1/6 )

-------------------------->  = 36/61


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