Plzz solve this guyzzzz ..I m always thankful to u plzz.solve by expla

1.	Plzz solve this guyzzzz ..I m always thankful to u plzz.solve by explanation and. step by step...
Answer» Solution : _________________________________ Answer - 1) : ________________ ⏭ Given: ✏ A scooterist travels a certain distance with speed of 50kmph and returns back at the STARTING point with a speed of 40kmph. ⏭ To Find: Average speed Average velocity ⏭ Concept: ✏ Average speed is defined as the RATIO of total distance covered to the total time taken. ✏ Average velocity is defined as the ratio of total DISPLACEMENT to the total time taken. ⏭ Calculation: Average speed $\mapsto \sf \: \tt{ \red{v_{av} = \dfrac{2 \times v_1 \times v_2}{v_1 + v_2}}} \\ \\ \mapsto \sf \: v_{av} = \dfrac{2 \times 50 \times 40}{50 + 40} \\ \\ \mapsto \sf \: v_{av} = \frac{4000}{90} \\ \\ \mapsto \: \boxed{ \tt{ \pink{ \large{av. \: speed = 44.44 \: kmph}}}}$ Average velocity $\implies \sf \: \red{displacement = zero} \\ \\ \because \sf \: \triangle{position} = zero \\ \\ \implies \: \boxed{ \tt{ \blue{ \large{av. \: velocity = zero}}}}$ _________________________________ Answer - 2) : ________________ ⏭ Given: ✏ A cyclist moves a distance of 30m from POINTS A to B in a straight line towards east with a speed of 10mps. ✏ He then moves a distance of 40m from poinr B to C in north direction with a speed of 20mps. ✏ Please see the attachment for better understanding. ⏭ To Find: Average speed Average velocity ⏭ Calculation: Average speed $\implies\sf \: av.speed = \dfrac{total \: distance}{total \: time}\\ \\ \implies\sf \: av.speed = \dfrac{30+40}{5} = \dfrac{70}{5} \\ \\ \implies \boxed{\tt{\large{\green{av.speed = 14 \: mps}}}}$ Average velocity $\mapsto\sf \: av.velocity = \dfrac{displacement}{time} \\ \\ \mapsto\sf \: av.velocity =\dfrac {50}{5}\\ \\ \mapsto \: \boxed{\tt{\large{\orange{av.velocity = 10\: mps}}}}\: \sf{(towards \: AC)}$

Plzz solve this guyzzzz ..I m always thankful to u plzz.solve by explanation and. step by step...

Answer»

Solution :

_________________________________

Answer - 1) :

________________

⏭ Given:

✏ A scooterist travels a certain distance with speed of 50kmph and returns back at the STARTING point with a speed of 40kmph.

⏭ To Find:

Average speed
Average velocity

⏭ Concept:

✏ Average speed is defined as the RATIO of total distance covered to the total time taken.

✏ Average velocity is defined as the ratio of total DISPLACEMENT to the total time taken.

⏭ Calculation:

Average speed

$\mapsto \sf \: \tt{ \red{v_{av} = \dfrac{2 \times v_1 \times v_2}{v_1 + v_2}}} \\ \\ \mapsto \sf \: v_{av} = \dfrac{2 \times 50 \times 40}{50 + 40} \\ \\ \mapsto \sf \: v_{av} = \frac{4000}{90} \\ \\ \mapsto \: \boxed{ \tt{ \pink{ \large{av. \: speed = 44.44 \: kmph}}}}$

Average velocity

$\implies \sf \: \red{displacement = zero} \\ \\ \because \sf \: \triangle{position} = zero \\ \\ \implies \: \boxed{ \tt{ \blue{ \large{av. \: velocity = zero}}}}$

_________________________________

Answer - 2) :

________________

⏭ Given:

✏ A cyclist moves a distance of 30m from POINTS A to B in a straight line towards east with a speed of 10mps.

✏ He then moves a distance of 40m from poinr B to C in north direction with a speed of 20mps.

✏ Please see the attachment for better understanding.

⏭ To Find:

Average speed
Average velocity

⏭ Calculation:

Average speed

$\implies\sf \: av.speed = \dfrac{total \: distance}{total \: time}\\ \\ \implies\sf \: av.speed = \dfrac{30+40}{5} = \dfrac{70}{5} \\ \\ \implies \boxed{\tt{\large{\green{av.speed = 14 \: mps}}}}$

Average velocity

$\mapsto\sf \: av.velocity = \dfrac{displacement}{time} \\ \\ \mapsto\sf \: av.velocity =\dfrac {50}{5}\\ \\ \mapsto \: \boxed{\tt{\large{\orange{av.velocity = 10\: mps}}}}\: \sf{(towards \: AC)}$