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Plz tell what is the meaning of described in this q |
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Answer» From Figure: Given ABCD is a square WHOSE one diagonal is AC. ΔAQC and ΔBPC are EQUILATERAL triangles on the diagonals AC and SIDE BC We know that Diagonal of square = √2 * length of the side of the square ⇒ Length of diagonal AC =√2 * BC ⇒ Area of (ΔBPC)/Area of (ΔAQC) = BC^2/AQ^2 = BC^2/(√2BC)^2 = BC^2/2BC^2 = 1/2. Therefore, area (ΔBPC) = (1/2) area (ΔAQC). Hope it helps! |
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