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Plz solve. this question |
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Answer» Answer: Step-by-step explanation: If x³-6x²+ax+b is exactly divisible by x²-3x+2, then it will ALSO be divisible by (x-1)(x-2)[Factors of x²-3x+2]. THEREFOR Putting X=1 in the equstion x³-6x²+ax+b-: 1-6+a+b = 0 a+b = 5 ---------EQ(i) putting X= 2 in the EQUATION x³-6x²+ax+b-: 8-24+2a+b = 0 2a+b = 16-------------eq(ii) On solving Eq 1 & 2 a=11 b=-6 |
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