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Plz solve it NO SPAM PLEASE |
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Answer» molecular mass=2× VAPOUR density Molecular mass=2×59=118 given in the question Carbon is 40.68%by mass assuming that one mole of compound is taken the weight of compound =molecular mass therefore Carbon's percentage mass will be =Mass of carbon÷total mass ×100 but this is equal to 40.68% 40.68%=mass of carbon/118×100 mass of carbon=40.68×118÷1009=48 Mass of Hydrogen/total mass ×100=5.08% Mass of hydrogen/118×100=5.08% Mass of hydrogen =5.08×118÷100=6 %of oxygen=100%-(5.08+40.68)% =54.24% Mass of oxygen/total mass×100=54.24% Mass of oxygen=54.24×118÷100=64 Mass of Carbon=48 Mass of Oxygen=64 Mass if Hydrogen=6 We know that molecular wt of
therefore their moles in compound
THEREFORE THE MOLECULAR FORMULA IS C4H6O4 |
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