Plz plz ans it..... I will surely mark as brainliest.

1.	Plz plz ans it..... I will surely mark as brainliest.
Answer» Step-by-step explanation: First in the part of the QUADRILATERAL, we can see their are 2 RESISTORS 14 ohm and 6 ohm. Now we can see they are in series, adding them we get the summation as 20 ohm. Now , we can see ANOTHER resistor in the diagonal as 20 ohm. We can see that the resultant and the diagonal are in parallel resistance. So, we apply parallel combination and get it as 1/20+1/20 = 2/20=10 ohm. Now this result is in series of the other 10 ohm. We get our next result as 20 ohm. Now again we have 20 ohm in parallel combination, so our result is 10 ohm and it is the equivalent resistance of the quadrilateral. Next we have 25 ohm in series . So adding it up our total resistance is 25+10=35ohm. Now to find current. We can find by the formula $voltage = current \times resistance$ Now we have voltage as 70 volts. 70= current×35 current= 2 AMPERES is the ANSWER

Answer»

Step-by-step explanation:

First in the part of the QUADRILATERAL, we can see their are 2 RESISTORS 14 ohm and 6 ohm.

Now we can see they are in series, adding them we get the summation as 20 ohm.

Now , we can see ANOTHER resistor in the diagonal as 20 ohm.

We can see that the resultant and the diagonal are in parallel resistance.

So, we apply parallel combination and get it as

1/20+1/20 = 2/20=10 ohm.

Now this result is in series of the other 10 ohm. We get our next result as 20 ohm.

Now again we have 20 ohm in parallel combination, so our result is 10 ohm and it is the equivalent resistance of the quadrilateral.

Next we have 25 ohm in series .

So adding it up our total resistance is

25+10=35ohm.

Now to find current.

We can find by the formula

$voltage = current \times resistance$

Now we have voltage as 70 volts.

70= current×35

current= 2 AMPERES is the ANSWER

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