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Plz help me in this numerical |
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Answer» Step-by-step explanation: Given :- a)2x + y = 7......(1) On putting X=0 in equation 1 2x+y=7 2×0+y=7 0+y=7 Y=7 So( 0, 7) is a solution of given equation. let y=0 2x+y=7 2x+0=7 2x=7 X= 7/2 So(7/2,0) is a solution of given equation.
let x = 1
2x+y=7 2×1+y=7 2+y=7 Y= 7-2 Y=5 (1,5) is the solution.
let x = 2 2x+y=7 2×2+y=7 4+y=7 Y= 7-4 Y= 3 The solution is (2,3) HENCE, 4 out of the infinitely many solutions of the given equation are(0,7), (7/2,0),(1,5),(2,3) |
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