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Plz answer me answer aor b only one of these |
| Answer» BACL2 =12.48gmolar mass of BaCl2 =208.23moles = mass /molar mass moles = 12.48/208.23moles =0.06 mass of water =1000g = 1 kgmolality = moles of BaCl2 / mass of solvent (kg)=0.06/1molality = 0.06m∆Tb = ∆T - ∆T•∆Tb =100.0832 - 100∆Tb = 0.0832∆Tb = i K b × mi = ∆ T b / k b × mi = 0.0832/0.52×0.06i =0.0832/0.0312i = 2.66BaCl2 ---> Ba 2+ + 2CL -total no of ions = 3 = na = i - 1 / n - 1 a = 2.66 - 1 / 3 - 1 a = 1.66 /2 a = 0.83a =83%a represents degree of dissociation(b )(π) osmotic pressure =6.8 atmM = 0.15T =310R = 0.082 L atm K ^-1 mol ^-1π V = i n R Tπ = i n/V RTπ = i M R Ti = π / M R T i = 6.8 / 0.15 ×0.082 × 310 i = 6.8/3.813i = 1.78K CL ---> K+ + Cl-n =2a = i - 1/ n-1a = 1.78 - 1/2-1a = 0.78/1a = 0.78a = 78% | |