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Plz ans it. I will mark brainliest

Answer» \bold{Answer :}

Now,

a²/bc + b²/ac + c²/ab

= (a³ + b³ + c³)/(ABC)

= {(a + B + c) (a² + b² + c² - ab - bc - CA) + 3abc}/(abc)

= { (0) (a² + b² + c² - ab - bc - ca) + 3abc}/(abc)

= (0 + 3abc)/(abc)

= (3abc)/(abc)

= 3

Identity RULE

a³ + b³ + c³ - 3abc

= (a + b + c) (a² + b² + c² - ab - bc - ca)

#\bold{MarkAsBrainliest}


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