1.

Pls solve this maths question(9 or 10 or both) its upto ur ability​

Answer»

Answer:

9.

for \: real \: roots \\ d > 0 \\ {b}^{2} - 4ac > 0 \\ {k}^{2} - 4 \times 1 \times - 4 > 0 \\ {k}^{2} + 16 > 0 \\ {k}^{2} > - 16 \\ k > \sqrt{ - 16}

10.

for \: real \: roots \\ d > 0 \\ {b}^{2} - 4ac > 0 \\ { - 2}^{2} - 4 \times k \times k > 0 \\ 4 - 4 {k}^{2} > 0 \\ - 4 {k}^{2} > - 4 \\ {k}^{2} > \frac{ - 4}{ - 4} \\ {k}^{2} > 1 \\ k > \sqrt{1} \\ k > + 1 \: or - 1

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