1.

Pls solve it...................​

Answer»

ANSWER:

GIVEN:

  • 1st Resistance = 6 Ω
  • 2nd Resistance = 6 Ω
  • 3rd Resistance = 6 Ω

TO FIND:

  • How would we connect the resistance to GET resultant as 9 Ω and 4 Ω.

SOLUTION:

To get 9 Ω EQUIVALENT Resistance:

We should connect two 6 Ω resinstance in PARALLEL then one 6 Ω resistance in series with the parallel combination.

\: \implies \:\dfrac{1}{r \: (parallel)} = \dfrac{1}{6} + \dfrac{1}{6} \\ \\ \implies \: \frac{1}{r(parallel)} = \dfrac{2}{6} \\ \\ \implies \: \frac{1}{r(parallel)} = \dfrac{1}{3} \\ \\ \implies \: r(parallel) = 3 \Omega \: \\ \\ \: now \: one \: 6 \Omega \: resistance \: are \: connected \: in \\ \: series \: with \: two \: 6 \: \Omega \: resistance \: connected \\ \: in \: parallel .\: \\ \\ equivalent \: resistance \: = 6 \Omega \: + 3\Omega \: \\ equivalent \: resistance \: = 9 \Omega \: \:


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