Saved Bookmarks
| 1. |
Pls answer the qn asap and also it's not there on any other website do don't go out searching and posting wrong and. Pls it's really imp |
| Answer» GIVEN :-Height of the tower = 30 mSpeed the ball THROWN from the bottom is 30 m/sTo find :-When will both the balls meet How to find :-Let's take that the ball thrown from the top of the tower (1 st particle) travels a distance (30 - x) and the ball dropped from the top (2 nd particle) travels x m.Let both the balls meet at a time 't'.For the first particle, By applying ------ (1)For the second particle,By applying ------ (2) (Here we GET -5 because the particle is moving opposite to the direction of g)Adding both the equations we get,100 = 30tt = 10/3 s = 3.333 SNOW substituting t = 3.333 s in the first equation we get , 30 - x ≈ 55.5 mx = - 25.5 m (Negative sign indicates opposite to the motion of particle)Hence both the particles meet at 25.5 m above the ground at 3.33 s.HOPE IT HELPS YOUPLEASE MARK ME AS THE BRAINLIEST | |