1.

Pls answer 12 question ​

Answer»

GIVEN

2( {a}^{2} + {b}^{2} ) = {(a + b)}^{2}

SIMPLIFICATION

2( {a}^{2} + {b}^{2} ) = {(a + b)}^{2} \\ \\ \\ \implies 2 {a}^{2} + 2 {b}^{2} = {a}^{2} + {b}^{2} + 2ab \\ \\ \\ \implies 2 {a}^{2} + {2b }^{2} - {a}^{2} - {b}^{2} = 2ab \\ \\ \\ \implies {a }^{2} + {b}^{2} - 2ab = 0 \\ \\ \\ \implies {(a - b)}^{2} = 0 \\ \\ \\ \implies a - b = 0 \\ \\ \\ \implies \: \boxed{a = b} \: \: (proved)

THEREFORE OPTION (B) is CORRECT .

IDENTITIES USED

(a+b)^2 = a^2 + b^2 + 2ab

(a-b)^2 = a^2 + b^2 - 2ab


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