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Answer»

Let the present ages of father and son be 'x' and 'y' respectively.

Given that, x + y = 45
So, x = 45-y

5 years ago,
Father's age = x-5
Son's age = y-5

Given, (x-5)(y-5) = 124

(45-y-5)(y-5) = 124

(40-y)(y-5) = 124

40y - 200 - y^2 + 5y = 124

y^2 - 45Y + 324 = 0

Solving the above quadratic equation, we get

We get y = 9
So x = 36

Thus, the present age of son is 9 years and the present age of father is 36 years .

Hope it HELPS!!


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