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Pls ans this as fast as possible

Answer»

TIME OF JOURNEY =5SECOUND

HEIGHT = 125m


✺ TOTAL DI STANCE =

125+125=250m


✸REASON✍✍✍

Object first go upward

and then fall BACK so total DISTANCE is addition
of both length

✺ TOTAL DISPLACEMENT


0

✷REASON ✍✍✍✍

DISPACEMENT is a VECTOR quantity it has


direction and magnitude


so
when body fall back then it is opposite

in direction.

=  > 125  + ( - 125)
=  > 0



✺ AVERAGE SPEED



\frac{total \: distance}{total \: time}





=  > \frac{250}{5}




=  > 50 \:  \: m {s}^{ - 1}




✺AVERAGE VELOCITY



\frac{total \: displacment}{total \: time}


\frac{0}{5}

ans \:  \:  \: 0



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