Plot the following points and write the name of figure thus obtained.

1.	Plot the following points and write the name of figure thus obtained. Find its perimeter. A (2, 0), B (4, 0), C (2,-2), D (4,-2)
Answer» ong>Figure we obtained is Rhombus and Area is 16 unit². Step-by-step explanation: GIVEN: Coordinates of the points, A( -4 , 4 ) , B( - 6 , 0 ) , C( -4 , -4 ) and D( -2 , 0 ) We need to plot the points in the coordinate plane and name the figure. Find the Area of the Figure. Graph is attached after plotting. ABCD is a Rhombus as opposite SIDES are parallel and all sides are EQUAL and Diagonals are PERPENDICULAR bisector of each other. Area of the Rhombus ABCD = Area of the ΔABD + Area of the ΔACD From the figure, In ΔABD Base = 4 unit HEIGHT = 4 unit In ΔACD Base = 4 unit Height = 4 unit Area of the Rhombus ABCD = 1/2 × Base × Height + 1/2 × Base × Height = 1/2 × 4 × 4 + 1/2 × 4 × 4 = 8 + 8 = 16 unit² Therefore, Figure we obtained is Rhombus and Area is 16 unit².

Plot the following points and write the name of figure thus obtained. Find its perimeter. A (2, 0), B (4, 0), C (2,-2), D (4,-2)

Answer»

ong>Figure we obtained is Rhombus and Area is 16 unit².

Step-by-step explanation:

GIVEN:

Coordinates of the points,

A( -4 , 4 ) , B( - 6 , 0 ) , C( -4 , -4 ) and D( -2 , 0 )

We need to plot the points in the coordinate plane and name the figure. Find the Area of the Figure.

Graph is attached after plotting.

ABCD is a Rhombus as opposite SIDES are parallel and all sides are EQUAL and Diagonals are PERPENDICULAR bisector of each other.

Area of the Rhombus ABCD = Area of the ΔABD + Area of the ΔACD

From the figure,

In ΔABD

Base = 4 unit

HEIGHT = 4 unit

In ΔACD

Base = 4 unit

Height = 4 unit

Area of the Rhombus ABCD = 1/2 × Base × Height + 1/2 × Base × Height

= 1/2 × 4 × 4 + 1/2 × 4 × 4

= 8 + 8

= 16 unit²

Therefore, Figure we obtained is Rhombus and Area is 16 unit².