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Answer»

R=√(P2 + Q2 + 2PQ cosѳ) R= √7Q √7Q =√(P2 + Q2 + 2PQ cosѳ) Squaring both sides 7 Q2 = P2 + Q2 + 2PQ cosѳ Ѳ = 60 Cos 60 = ½ 6 Q2 = P2 + PQ Partitioned by Q2 6 = (P/Q)2 +P/Q LET P/Q be X x^2 +x – 6 = 0 x^2 + 3x-2x - 6 = 0 x(x+3)- 2(x+3) = 0 (x+3)(x-2) = 0  x =-3 ,x =2  P/Q =2


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