Saved Bookmarks
| 1. |
Please solve this the answers written in boxes are wrong |
|
Answer» From the FIGURE LET the height perpedicular at AM be O WKT M is the mid POINT so, AM=MB (i) In triangle AMC ½*b*h ½*AM*CO ------- (ii) In triangle BMC ½*b*h ½*AM*CO ------(iii) On solving (ii) and (iii), we get Ar. of triangleAMC=Ar. of triangleBMC Hence proved Hope this HELPS you...... |
|